False. Over constrained, and not defining a single flat plane of the form:
Ax+By+Cz+D=0
Wolfram-Alpha inputs for the first 3 and last 3 sets of coordinates:
plane through (1,3,1) and (1,1,-1) and (-1,1,1)
plane through (1,1,-1) and (-1,1,1) and (1,2,1)
define different equations => different planes => therefore all 4 points do NOT lie on a common plane.
coplaner points- are points lying on his the same plane,.. solution: plane R contains XY XY contains X and Y...
There can be any number of points on a plane, or even on a line - and any number of lines on a plane.
Four non-collinear points can form exactly one plane. This is because a plane is defined by three non-collinear points, and adding a fourth point that is not in the same line as the other three does not create a new plane; rather, it remains within the same plane defined by the initial three points. Therefore, all four points lie in the same unique plane.
If they lie in the same plane.
-lie in the same plane -are collinear
coplaner points- are points lying on his the same plane,.. solution: plane R contains XY XY contains X and Y...
No. If the four points are coplanar, they determine only one plane!
There can be any number of points on a plane, or even on a line - and any number of lines on a plane.
Any 4 points can lie in a plane, 3 points determine a plane and just take the 4th to be say the origin.
points
yes
Four non-collinear points can form exactly one plane. This is because a plane is defined by three non-collinear points, and adding a fourth point that is not in the same line as the other three does not create a new plane; rather, it remains within the same plane defined by the initial three points. Therefore, all four points lie in the same unique plane.
all of them are collinear they lie in the same plane
If they lie in the same plane.
lie on the same plane and are collinear
-lie in the same plane -are collinear
yes if it is a square of recatgle