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∙ 7y ago47
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∙ 7y agoTo answer this question you first need to break 135 down into its prime factors: 135 = 3x3x3x5 In order to find two numbers that multiply to make 135, one of them must be a product of a certain combination of these numbers (and 1) and the other must have the rest. Therefore the possible pairs are: 1 and 135 3 and 45 5 and 27 9 and 15
44 + 45 + 46 = 135
44 + 45 + 46 = 135
It is: 3*3*3*5 = 135
As a product of its prime factors: 3*3*3*5 = 135
45, 90 and 135
Factorization of 135The factorization of 135 is:1 X 1353 X 455 X 27Factorization should not be confused with prime factorization. Prme factorization of 135 is:3 X 453 X 5 X 93 X 5 X 3 X 3Putting the factors in order from smallest to largest, the prime factorization of 135 is:3 X 3 X 3 X 5
To answer this question you first need to break 135 down into its prime factors: 135 = 3x3x3x5 In order to find two numbers that multiply to make 135, one of them must be a product of a certain combination of these numbers (and 1) and the other must have the rest. Therefore the possible pairs are: 1 and 135 3 and 45 5 and 27 9 and 15
There are no such numbers but if you meant -135 then the numbers are -9 and 15
1,5,9,15,27, and 135. I might be missing some numbers, though.
44 + 45 + 46 = 135
44 + 45 + 46 = 135
Given the sum of three consecutive integers 135, we write out the expression as:x + (x + 1) + (x + 2) = 135 where:x = smallest integerx + 1 = middle integerx + 2 = largest integerSolve for x by rearranging the terms:3x + 3 = 1353x = 132x = 44Therefore, the largest integer is x + 2 = 46.
Numbers such as 135, 270, 405, and other multiples of 135.
30 and 135 both are composite numbers. 30 and 135 both are divided by 5 and 3.
Prime numbers between 135 and 145 are: 137 and 139.
Perfect cubes smaller than 135 are 1, 8, 27, 64, and 125. Of these, 1 and 27 are factors of 135, so 27 is the largest factor of 135 that is a perfect cube.