The sum of the four angles is 360 degrees. Three of the angles add up to 310 so the fourth must be 360 - 310 = 50 degrees.
120 is 120% of 100.
120, if it is a polygon.
100*12/120 = 10%100*12/120 = 10%100*12/120 = 10%100*12/120 = 10%
The bond angles are 120 degrees
The sum of the four angles is 360 degrees. Three of the angles add up to 310 so the fourth must be 360 - 310 = 50 degrees.
50 degrees (360 degrees in a quadrilateral)
The sum of the internal angles of a quadrilateral is 360 degrees. Therefore given the three angles 60, 120, and 90, the fourth would be (360) - (60 + 120 + 90) = 360-270 = 90 degrees
Sum of angles in a quadrilateral is 360° Three angles sum to 80° + 120° + 65° = 265° Therefore the missing fourth angle is 360° - 265° = 95°
It is: 360-80-120-65 = 95 degrees which is the 4th angle
There are 6 angles in a hexagon, and each angle measures 120 degrees. 120 x 6, or 120+120+120+120+120+120=720.
The sum of the angles in a trapezoid is 360 degrees, therefore, the forth angle in this problem is: 360 - (60+120+80) = 100 degrees
120 is 120% of 100.
120, if it is a polygon.
Supplement angles = 180° So 180° - 120° = 60° Complementary angles = 90°
100*12/120 = 10%100*12/120 = 10%100*12/120 = 10%100*12/120 = 10%
The bond angles are 120 degrees