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Suppose the number, when written is XY.

Then sum of digits = 10 implies that X+Y = 10

Also, 20 < XY < 32 implies that X = 2 or 3.

Suppose X = 3

Then X+Y = 10 requires Y = 7. But that is not possible because the number cannot be greater than 32.

So, X must be 2.

And then, X+Y = 10 implies that Y = 8 and so the number is 28.

Q: Robert's numbers is between 20 and 32 the sum of the digits is 10 what is the number how do i solve it?

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28

The sum of the number of digits in all the numbers between 31 and 400 inclusive is 1041.

The answer is 28

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20 number

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28

The number is: 36725918 In descending order that is: 98765321 The pairs of numbers that have as many digits between them in both are: 3,9 5,8 6,7 So there are three pairs.

The sum of the number of digits in all the numbers between 31 and 400 inclusive is 1041.

Digits is how many numbers you have in a number. If you have the number 4 it has one digit if you have the number 20 it has two digits and if you have the number 558 it has three digits. So basically in the number 1085 it has 4 digits because there is 4 numbers in it, the numbers are 1,0,8 and 5. Hoped you understand.

This cannot be answered. This will have to be written to where it can be understood.

The answer is 28

20 number

That is a trick question. 10 is the same number as 10.000, it is merely expressed with fewer significant digits. There are no numbers between one number and itself.

Armstrong numbers are the sum of their own digits to the power of the number of digits.

There is only one integer between these two numbers which contains both the digits 7 & 4.It is 347.

Since both of those numbers contains four digits, there are no three-digit numbers between them.

infintate as numbers do not stop, so you can keep adding digits at the end of the negative number.