No. The diagonals of a parallelogram are congruent if and only if the parallelogram is a rectangle.
Yes because a rhombus is like a parallelogram
square
No because the diagonals of a parallelogram are of different lengths
Opposite angles are congruent in a parallelogram.
They are sometime congruent because a square is a parallelogram and its sides are congruent and a rectangle is one and its sides aren't congruent.
rectangle and parallelogram
Yes because a rhombus is like a parallelogram
square
No. The diagonals are perpendicular, but they dont have to be congruent.
Always. In fact, one method of proving a quadrilateral a rhombus is by first proving it a parallelogram, and then proving two consecutive sides congruent, diagonals bisecting verticies, etc.
Yes the diagonals of a square are always congruent. Their length is a*root 2 where a is the side of the square.
No, the diagonals of a trapezoid are not always congruent. A trapezoid is a quadrilateral with at least one pair of parallel sides. The diagonals of a trapezoid connect the non-parallel vertices, and their lengths can vary depending on the specific dimensions of the trapezoid. In a trapezoid where the non-parallel sides are of equal length, the diagonals will be congruent, but this is not always the case.
In a quadrilateral, the diagonals are only congruent for rectangles (or squares, which is a special kind of rectangle). Note: they are not congruent for a Rhombus.
No because the diagonals of a parallelogram are of different lengths
No sucka
Regular polygons. A square and rectangle will have congruent (equal length) diagonals.
A square and a rectangle have diagonals of the same lengths.