No because the diagonals of a parallelogram are of different lengths
The statement is no true.
To construct a parallelogram with one side and two diagonals given, start by drawing the given side as one of the sides of the parallelogram. Label the endpoints of this side. Then, using a compass, draw arcs from each endpoint of the side with radii equal to the lengths of the diagonals, intersecting at two points. These intersection points will be the other two vertices of the parallelogram. Finally, connect these vertices to form the complete parallelogram.
The given vertices when plotted on the Cartesian plane forms a rectangle with diagonals of square root of 50 in lengths and they both intersect at (3.5, 4.5)
The point where the perpendicular bisectors of the sides of a triangle intersect is called the circumcenter. This point is equidistant from all three vertices of the triangle and serves as the center of the circumcircle, which is the circle that passes through all the vertices of the triangle.
They are diagonals. In a rhombus, diagonals join opposite vertices.
sometimes
sometimes
The statement is no true.
To construct a parallelogram with one side and two diagonals given, start by drawing the given side as one of the sides of the parallelogram. Label the endpoints of this side. Then, using a compass, draw arcs from each endpoint of the side with radii equal to the lengths of the diagonals, intersecting at two points. These intersection points will be the other two vertices of the parallelogram. Finally, connect these vertices to form the complete parallelogram.
Suppose that the parallelogram is a rhombus (a parallelogram with equal sides). If we draw the diagonals, isosceles triangles are formed (where the median is also an angle bisector and perpendicular to the base). Since the diagonals of a parallelogram bisect each other, and the diagonals don't bisect the vertex angles where they are drawn, then the parallelogram is not a rhombus.
The three major diagonals in an ordinary hexagon do not intersect at the same point. Therefore, in such a hexagon, the diagonals form 111 triangles.
The given vertices when plotted on the Cartesian plane forms a rectangle with diagonals of square root of 50 in lengths and they both intersect at (3.5, 4.5)
Not sure about vertices's. The circumcentre is equidistant from a triangle's vertices (no apostrophe).
No. and it is not vertices's! vertices will do.
The vertices of a rhombus have no right angles but its diagonals intersect each other at right angles.
The point where the perpendicular bisectors of the sides of a triangle intersect is called the circumcenter. This point is equidistant from all three vertices of the triangle and serves as the center of the circumcircle, which is the circle that passes through all the vertices of the triangle.
They are diagonals. In a rhombus, diagonals join opposite vertices.