In 100 numbers you can select 50 all odd or 50 all even and there will be no consecutive pair. Picking another number must be of the opposite parity and so consecutive with one of your first 50.
The least of the three numbers is 199.
To guarantee that one of the consecutive numbers is 6, you need to include the number 6 itself. Therefore, if you select a sequence of consecutive numbers that includes 6, you can choose any range that contains it, such as 5, 6, and 7. Thus, you need at least 1 number (specifically the number 6) to guarantee that one of those numbers is 6.
Yes because at least one of the consecutive numbers will be even, and if you times anything by an even number, the answer will always be even
No. Any three consecutive numbers will have at least one of them which is divisible by 2, which means it cannot be prime. And since 1 is not considered a prime number, it cannot happen.
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
The least of the three numbers is 199.
No, because every other number in the number line is odd so therefore if you have any number of consecutive numbers you will have at least one odd number (if you're talking about consecutive numbers on a number line).
Yes because at least one of the consecutive numbers will be even, and if you times anything by an even number, the answer will always be even
No. Any three consecutive numbers will have at least one of them which is divisible by 2, which means it cannot be prime. And since 1 is not considered a prime number, it cannot happen.
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
Every sixth number will be a multiple of 6, so you need at least six consecutive numbers to guarantee that one of them will be divisible by 6.
The expression 2x3x4x5 can be simplified to 120. The number 120 has the least number of factors because it is a product of consecutive prime numbers (2, 3, and 5). When a number is a product of distinct prime numbers, it will have fewer factors compared to numbers with repeated prime factors. In this case, 120 only has 16 factors, making it the least among numbers with the same number of prime factors.
Select ALL pairs of numbers that have a least common multiple of 30
Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.
That is the median average!
Yes, the product of any three consecutive numbers is divisible by 6. This is because among any three consecutive integers, at least one of them is even (ensuring divisibility by 2), and at least one of them is divisible by 3. Since 6 is the product of 2 and 3, the product of any three consecutive numbers is therefore divisible by 6.
3 consecutive numbers cannot be prime factors. Any three consecutive numbers would include at least one even number. The only even prime number is 2, and (2,3,4) doesn't qualify.