Yes, the product of any three consecutive numbers is divisible by 6. This is because among any three consecutive integers, at least one of them is even (ensuring divisibility by 2), and at least one of them is divisible by 3. Since 6 is the product of 2 and 3, the product of any three consecutive numbers is therefore divisible by 6.
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
Their sum is 15.
6,12,18.
The sum of any three consecutive even numbers must be divisible by 3. 32 is not, so there is no solution.
0, 1, 2
There must be three consecutive integers to guarantee that the product will be divisible by 6. For the "Product of three consecutive integers..." see the Related Question below.
No. Every third consecutive natural number is divisible by 3.
Not sure what thress is. If three, then there is no answer since the sum (or product) of any three consecutive integers must be divisible by 3.
18
That doesn't work. The number has to be divisible by three. Any three consecutive numbers add up to a multiple of three.
Any three consecutive integers are divisible by three because it can be shown that the sum divided by three is the middle number.
Yes, if the first number is odd.
0,6,18,36,60,90,126,168, etc
Their sum is 15.
6,12,18.
The sum of any three consecutive even numbers must be divisible by 3. 32 is not, so there is no solution.
0, 1, 2