Let's simplify this together, friend. To solve the equation 2t^2 + 8t + 5 = 0, we can use the quadratic formula or factor it. If we factor, we look for two numbers that multiply to 2*5=10 and add up to 8. Once we find those numbers, we can rewrite the equation in factored form to find the solutions for t. Just take your time and enjoy the process of unraveling this mathematical mystery.
89+2t = 10t+25 89-25 = 10t-2t 64 = 8t t = 8
12t + 15
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
6t2+17t+7 = (3t+7)(2t+1) when factored
R = S + 2T S = 3T .... substitute R = (3T) + 2T R = 5T
2t
t+t=2tand t*t= t squaredyou would only get t squared if you multiplied
In 2t+8 19
89+2t = 10t+25 89-25 = 10t-2t 64 = 8t t = 8
12t + 15
75+2t=100-2t 4t=25 t=6.25 So t is 6.25 or 25/4.
12(t+6)+8=4(2t-1)+2t 12t+72+8=8t-4+2t 12t-2t-8t=-72-8-4 2t=-84 2t/2=84/2 t=42
3t + 7 = 2t - 5 3t = 2t - 12 t = -12
24
6t2+17t+7 = (3t+7)(2t+1) when factored
1xy
(t+h)(x+2)