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6xy(2x2 - 3y)
5xy+4=9 is the problem, right? 5xy+4=9. Now subtract the 4 from both sides. 5xy=5. Ok, then, that looks less scary. Now, divide both sides by 5, to get xy=1. Hmm, a lot simpler. Now, divide both sides by x to get y by itself. So, y=1/x. Alright. That's your line! No, its not a straight line. There is a vertical asymptote where x=0, and the two segments aren't straight. But that's a simpler form of the equation. Hope that helped!
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
There are 2 interpretations of your question: First: e^[lnx + lny] =e^[ln(xy)] =xy Second: lny + e^(lnx) =lny + x