0
6xy(2x2 - 3y)
5xy+4=9 is the problem, right? 5xy+4=9. Now subtract the 4 from both sides. 5xy=5. Ok, then, that looks less scary. Now, divide both sides by 5, to get xy=1. Hmm, a lot simpler. Now, divide both sides by x to get y by itself. So, y=1/x. Alright. That's your line! No, its not a straight line. There is a vertical asymptote where x=0, and the two segments aren't straight. But that's a simpler form of the equation. Hope that helped!
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
There are 2 interpretations of your question: First: e^[lnx + lny] =e^[ln(xy)] =xy Second: lny + e^(lnx) =lny + x
(2x - 3y)(x + y)
(-5xy):(-xy)=
xy(7+2y-3x)-6xy
3, since the degree of a polynomial is equivalent to its highest power.
The coefficient of xy is the number that multiplies the product of x and y in a given expression. For example, in the expression 5xy, the coefficient of xy is 5.
0
If x - 3y = 12, we can solve for x in terms of y: x = 12 + 3y. Then, to find xy, we multiply x by y: xy = y(12+3y) = 12y + 3y^2.
(x - 1)(2x + y)
2/y
4
6xy(2x2 - 3y)
You cannot have xy= anything. Only x can be there at the end. x=5y=5 Divide 5y for all 3 sides to get 5xy=y Then divide y from both sides to get 5x=1 Therefore, x=1/5