5xy+4=9 is the problem, right?
5xy+4=9. Now subtract the 4 from both sides. 5xy=5. Ok, then, that looks less scary. Now, divide both sides by 5, to get xy=1. Hmm, a lot simpler. Now, divide both sides by x to get y by itself. So, y=1/x. Alright. That's your line! No, its not a straight line. There is a vertical asymptote where x=0, and the two segments aren't straight. But that's a simpler form of the equation. Hope that helped!
No.No.No.No.
9
All six of them
It is: 7a/5xy
4x^2+2xy-3y^2-2x^2+5xy-2y2Collect the like terms=2x^2+7xy-5y^2We cannot factorise it because the end term is a negative whilst the second-last term is positive.
5xy+4=9
No.No.No.No.
Without an equality sign the given expression can't be considered to be a linear equation.
colinear and non-colinear are terms that are used when describing points in space, not the graph of a function. Maybe what you meant is "Is the function linear?" The answer to that question is no.
9
x2 + 5xy - 18y2 can not be factored.
What is : 5xy- x2t + 2xy + 3x2t
1xy
1xy
It is 5xy + 5x.
The GCF is 5xy.
All six of them