The general formula for acceleration is [(final velocity) - (initial velocity)]/(time required for the change). In this instance, (5 - 65)/0.75 = -80 meters per second per second.
80 m/s down
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
80 m/s2 up
80 m/s 2 up
If the 0.75 refers to seconds, then his acceleration is -66.66... (repeating) metres per second^2.
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
the magnitude of the skydivers acceleration is zero as he is decelerating by opening his parachute!
66.7 m/s2
80 m/s2 up
66.7 m/s2
80 m/s 2 up
If the 0.75 refers to seconds, then his acceleration is -66.66... (repeating) metres per second^2.
To calculate this, you divide the change in velocity, by the time.
He will decelerate (meaning an acceleration in the direction opposite of current velocity) at a rate of (54 m/s - 4 m/s)/.75 seconds = 66.67 m/s2. This is about 6.8 Gs.
Only if they have a heart attack, but not likely.
66.7 m/s2
(4 m/s - 54 m/s)/0.75 s = -50/0.75 m/s² = -200/3 ≈ - 66.67 m/s² (negative because he is decelerating)
Maximum speed is about 220 to 230mph and can be achieved after about 20 seconds of freefall. Normal parachute opening speed should be not greater that 120mph to avoid damage to the parachute