a = 4
-2a + 5 = 1 -2a = -5 + 1 -2a = -4 a = -4/-2 a = 2
If: 2a+13 = 5a+1 Then: a = 4
a+a=1 2a=1 a=1/2
a + a + a - 2a = 3a - 2a = a
Solve the following equation for A : 2A/3 = 8 + 4A
the answer
2a + 2b = 160 But b = a + 40 so 2a + 2(a + 40) = 160 ie 2a + 2a + 80 = 160 or 4a = 80 ie a = 20 Then b = a + 40 gives b = 20 + 40 = 60 Solution: a = 20, b = 60
:a = .5(hb+c) :2a = hb+c :2a−c = hb :(2a−c)/h = b
2a+5a+9a = 16a
To solve this, isolate x. first, add 10 to both sides. this will leave you with 2a + 15 = a Then, subtract 2a from both sides. This will leave you with 15 = -a Therefore, -15 = a
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------