2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
y=4x-8y=2x+10Substitute (4x-8) for y in the second equation and solve for x:4x-8=2x+102x=18x=9Now solve for y:y=4(9)-8=28(9,28)
Not enough information to solve
Using the quadratic equation formula: x = 1 or x = -10
x = -8
2x2+18x = 20 2x2+18x-20 = 0 x2+9x-10 = 0 (x+10)(x-1) = 0 x = -10 or x = 1
y=4x-8y=2x+10Substitute (4x-8) for y in the second equation and solve for x:4x-8=2x+102x=18x=9Now solve for y:y=4(9)-8=28(9,28)
Not enough information to solve
10
Using the quadratic equation formula: x = 1 or x = -10
With a calculator.
x=35
x = -8
A + 10 = 7.9Subtract 10 from each side:A = 7.9 - 10 = -2.1
x2=18x-80 (im guessing you are trying to find x) x2-18x+80=0 (x-10)(x-8)=0 Therefore: x = 10, 8
a + 4 = 10(a + 4) - 4 = 10 - 4a = 6
If 6x + 10 = 11x , then x=2.