Since b2 is doubled by adding 3, b2 equals 3. 1/2 of that is b, hence b=1-1/2.
y=5
If we assume that it equals zero and you wish to solve for x, then the answer is:-x2 + 2x - 3 = 0x2 - 2x + 3 = 0x2 -2x + 1 = -2(x - 1)2 = -2x - 1 = ± √(-2)x = 1 ± i√2
you mean: y= -3x+1 y+x=-3+1 solve -3+1= -2 y+x = -2
3x-1 = 7 3x = 8X= 8/3 = 2+2/3
Since b2 is doubled by adding 3, b2 equals 3. 1/2 of that is b, hence b=1-1/2.
y=5
If we assume that it equals zero and you wish to solve for x, then the answer is:-x2 + 2x - 3 = 0x2 - 2x + 3 = 0x2 -2x + 1 = -2(x - 1)2 = -2x - 1 = ± √(-2)x = 1 ± i√2
-(4-3) -(1) -1
4t-1 = t+2 3t -1 = 2 3t = 3 t = 1
4x2 - 2x - 3 = 0 (2x + 1)(2x - 3) = 0 x = -(1/2) or (3/2)
-2 plus 5 equals +3
you mean: y= -3x+1 y+x=-3+1 solve -3+1= -2 y+x = -2
3x-1 = 7 3x = 8X= 8/3 = 2+2/3
If: 2x-1 = 2Then: 2x = 2+1And: 2x = 3So: x = 3/2 = 1.5 or 1 and a 1/2
8 1/3 = ab^-1, 1.8 =ab^2
3