(5 + 4 - 3 - 2) x 1 = 4
3x + 4= 7 3x= 7-4 3x/3 = 3/3 x=1
3
6x+2y=4 gives y=2-(1/3)x
10
a = 4
You would do it it by oppisites. 3+2+4=9 which equals C.
i dont know what you are trying to solve for, but if you are solving for x and y. u have to...... 3x-4y=4 x= 4/3..... 1.33 y=4/-4...... -1
5x+3 = x+4 5x-x = 4-3 4x = 1 x = 1/4 Thats not even close to how you solve it. First of all the equation is written 5^(x+3)=x+4. Simple Logarithms are needed to solve.
If: x+y = 4 and y = 2x+1 Then: 4-x = 2x+1 => 3 = 3x => 1 = x So by substitution: x = 1 and y = 3
y + 2y = 4 (2+1)y = 4 3y = 4 (3y)/3 = 4/3 y = 4/3 = 1.3333333333333333333
x=4 y=x+3 y=4+3 y=7