7x + 2 = 5,6
Subtract by 7x and divide by 2.
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
7x = 3x - 12 4x=-12 x=-3
7x+2-2=16-27x = 147x/7 = 14/7x = 2
7x + y = 4y = 4 - 7x
7x + 2 = 5,6
Subtract by 7x and divide by 2.
7x + y = 8 Subtract 7x from each side of the equation: y = -7x + 8
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
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There is no symbol between 7x and 31. Please resubmit using words eg "plus", "equals" etc.
7x = 3x - 12 4x=-12 x=-3
(3,3)
7x+2-2=16-27x = 147x/7 = 14/7x = 2
4x+9 = 7x+3 4x-7x = 3-9 -3x = -6 x = 2
7x + 8 = 11x + 3, solve for xsubtract 7x from both sides8 = 11x - 7x + 38 = 5x + 3subtract 3 from both sides5 = 5xdivide both sides by 51 = x.