How do you solve 4y plus x equals 8
8-5(2+x)=2(x+1)
Factor it. (x - 8)(x - 2) x = 2, 8
i don't get that if it is 2xy +8 or 8 + 2xy then you can't solve or simplify it any further if it were 8 x 2y then you time the 8 by the 2 to get 16y
2x+8=10... Subtract 8 on both sides, then devide by 2... 2x=2... x=1
How do you solve 4y plus x equals 8
8-5(2+x)=2(x+1)
Factor it. (x - 8)(x - 2) x = 2, 8
x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
2x+8 = 6 2x = 6-8 2x = -2 x = -1
(x-2)(x-4) x=2,4 ans
i don't get that if it is 2xy +8 or 8 + 2xy then you can't solve or simplify it any further if it were 8 x 2y then you time the 8 by the 2 to get 16y
2x+8=10... Subtract 8 on both sides, then devide by 2... 2x=2... x=1
If the equation is structured like this: (8/x)=(12/(x+2)) then x=4. If the equation is structured like this: (8/x)=(12/x)+2 then x=-2.
2
in order to solve this problem you have to solve for x first wich you are given the data to pre forme so x=4 and x.2=8 and 8=y and y-4=4=a=x so a+8=12 and 12=b
As you've written it, it can't be solved. I'll assume you mean -2x plus 8=2. -2x=-6. x=3.