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The first part of the equation is the square of the second part, since 100 is 10 squared and the square of 2x is 22x. Writing y for 10/2x, we get the quadratic equation y2 + y = 1. Using the quadratic formula, we get y = (-1 + or - square root of 5)/2. Since real powers of 2 are all positive, we take the positive square root. Substituting for y and solving for x, we get x = log2(20/((square root of 5)-1)). You can calculate the value of this by using a scientific calculator, using the fact that log of a number to the base 2 is the natural log of the number divided by the natural log of 2. I get about 4.016.

Q: Solve for x if 1 equals first part of equation 100 divided by 2 to the power of 2x plus second part of equation 10 divided by 2 to the power of x?

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Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".

No. There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.

This equation is unsolvable since there are two unknowns and only one equation. You would require a second equation in order to solve it.

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5x = 80

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Since the second equation is already solved for "y", you can replace "y" by "9" in the other equation. Then solve the new equation for "x".

No. There is not enough information in the equation x + 2y = 2, by itself, to solve it. There are an infinite number of solutions. A second equation, or information to allow a second equation to be derived, must be given to find a solution.

This equation is unsolvable since there are two unknowns and only one equation. You would require a second equation in order to solve it.

It is not an equation if it does not have an equals sign. You could simplify it but not solve it.

if the equation was 7x = 42. The answer would be x = 6

a equals 5

You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".

You would need one more equation relation x and y to solve for both of them.

In the equation: F is force, m is mass, and a is acceleration. Divide both sides by a, and you have:m = F/a, which is Force divided by acceleration.