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Solve the following systems of simultaneous linear equations using Gauss elimination method and Gauss-Seidel Method

2x1+3x2+7x3 = 12 -----(1)

x1-4x2+5x3 = 2 -----(2)

4x1+5x2-12x3= -3 ----(3)

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Q: Solve the following systems of simultaneous linear equations using Gauss elimination method and Gauss-Seidel Method?

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Graphs can be used in the following way to estimate the solution of a system of liner equations. After you graph however many equations you have, the point of intersection will be your solution. However, reading the exact solution on a graph may be tricky, so that's why other methods (substitution and elimination) are preferred.

That would depend a lot on the specific equations. Often the following tricks can help: (a) Take antilogarithms to get rid of the logarithms. (b) Use the properties of logarithms, especially: log(ab) = log a + log b; log(a/b) = log a - log b; log ab = b log a. (These properties work for logarithms in any base.)

b,c

Since there are no equations following, the answer must be "none of them".

The answer follows:

Related questions

Simultaneous equations have at least two unknown variables.

Since there are no "following" equations, the answer is NONE OF THEM.Since there are no "following" equations, the answer is NONE OF THEM.Since there are no "following" equations, the answer is NONE OF THEM.Since there are no "following" equations, the answer is NONE OF THEM.

I notice that the ratio of the y-coefficient to the x-coefficient is the same in both equations. I think that's enough to tell me that their graphs are parallel. So they don't intersect, and viewed as a pair of simultaneous equations, they have no solution.

Graphs can be used in the following way to estimate the solution of a system of liner equations. After you graph however many equations you have, the point of intersection will be your solution. However, reading the exact solution on a graph may be tricky, so that's why other methods (substitution and elimination) are preferred.

You can experiment with different numbers (trial-and-error). You can also write this as simultaneous equations: a + b = 50 (the sum of the two numbers is 50) a - b = 10 (the difference is 10) There are several approaches to simultaneous equations; in this case, it is easy to solve by adding the two equations together: a + b + a - b = 60 2a = 60 a = 30 So, the first number is 30. You can get the second number by replacing in any of the original equations.

Which of the following is a disadvantage to using equations?

Which of the following what?

It would help very much if the "following equations" actually DID follow!

That would depend a lot on the specific equations. Often the following tricks can help: (a) Take antilogarithms to get rid of the logarithms. (b) Use the properties of logarithms, especially: log(ab) = log a + log b; log(a/b) = log a - log b; log ab = b log a. (These properties work for logarithms in any base.)

If they are quadratic equations then if their discriminant is less than zero then they have no solutions

The following equations is correct

2na+s-2nas