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What is the solution set of the equation x squared minus 3x minus 4 equals 0?
X2 - 3X - 4 = 0factored(X + 1)(X - 4)----------------X = - 1X = 4-------------------(- 1, 0) and (4, 0)================solution set of X interception points
Is it possible for a sixth-degree polynomial to have only one solution?
Yes. y = x6 has only one solution, at (0, 0).In fact, if you think about it, the family of equations y = a(x+b)6 (where a and b can be any real constant; including x6, 2(x-4)6, 42(x+1)6, and so on) all have one solution. Other than these equations, however, sixth-degree polynomials almost always have multiple solutions or none at all.
Use addition or substitution to find the value of x for this set of equations 2x - 3y equals -15 x equals 4y?
2x - 3y = -15x => -3y = -17x => -21y = -119x 2x - 3y = 4y => 2x = 7y => 21y = 6x so now you can add the two equations. 0 = -113x x=0 now plug back in 2*0 - 3y = -15*0 -3y = 0 y=0.
Which is the solution set for 3x2 - 4x - 15 equals 0?
3x2-4x-15 = 0 (3x+5)(x-3) = 0 x = -5/3 or x = 3
Sin x cos x equals 0?
For the product to be zero, any of the factors must be zero, so you solve, separately, the two equations: sin x = 0 and: cos x = 0 Like many trigonometric equations, this will have an infinity of solutions, since sine and cosine are periodic functions.
