-9h - 6 + 12h + 40 = 22 ie 3h = 22 + 6 - 40 h= -12/3 = -4
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
-9-6+12h+40=22
h-9h-6+12h+40 = 22 h-9h+12h = 22+6-40 4h = -12 h = -3
-9h-6+12h+40 = 22 3h+34 = 22 3h = 22-34 3h = -12 h = -4
-9h-6+12h+40=22 -9h+12h=22-40+6 3h=-12 h=-4
-9h - 6 + 12h + 40 = 22 ie 3h = 22 + 6 - 40 h= -12/3 = -4
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
-9h-6+12h+40=22
-9-6+12h+40=22
-9h - 6 + 12h + 40 = 22, simplifying this gives12h - 9h + 40 - 6 = 223h + 34 = 22, taking 34 off both sides gives3h + 34 - 34 = 22 - 343h = -12, thush = -12/3 = -4
It is not an equation because there's no equal sign but some kind of algebraic expression.
h-9h-6+12h+40 = 22 h-9h+12h = 22+6-40 4h = -12 h = -3
The balanced equation is: 4AlโCโ + 12HโO โ 4Al(OH)โ + 3CHโ. This equation is balanced by ensuring that the number of each type of atom is the same on both sides of the equation.
-9h-6+12h+40 = 22 3h+34 = 22 3h = 22-34 3h = -12 h = -4
It is: 12h+5h = 17h
if the question is A12bh, then the right hand side of the equation should equal to 0. so: A X 12 X b X h = 0 b = A/12 X 1/h so: b = A/12h