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How do you solve -x2 plus 2x-3?
If we assume that it equals zero and you wish to solve for x, then the answer is:-x2 + 2x - 3 = 0x2 - 2x + 3 = 0x2 -2x + 1 = -2(x - 1)2 = -2x - 1 = ± √(-2)x = 1 ± i√2
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
What is x3-x2 plus 2x factored?
x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.
2x equals x2 plus 4x-3?
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
How do you solve -x2 plus 2x-3?
If we assume that it equals zero and you wish to solve for x, then the answer is:-x2 + 2x - 3 = 0x2 - 2x + 3 = 0x2 -2x + 1 = -2(x - 1)2 = -2x - 1 = ± √(-2)x = 1 ± i√2
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
Solve x2 plus 2x - 13 equals 2?
x2 + 2x - 13 = 2 x2 + 2x - 15 = 0 (x + 5)(x - 3) = 0 x + 5 = 0 and x - 3 = 0 so x = -5 and x = 3
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
What is x3-x2 plus 2x factored?
x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.
2x equals x2 plus 4x-3?
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
What is x2 plus 2x equals 0?
x2+2x=0 4x=0 x=0 if you meant soemthing times 2 plus 2 times x =0 solve for x then y2+2x=0 y+x=0 x=-y so if x is 2 y is -2, if x is 100 y is -100
Is this a factor x2 plus x plus 1?
It can be. x^2 + x + 1 is a factor of 2x^2 + 2x + 2
Solve X2 plus -2x -5.25 equals 0?
x = 7/2 and also x = -3/2 by using the quadratic equation formula.
How do you solve 2x plus 2?
The solution to the equation 2x plus 2 is 2(x + 1).
What are the zeros of x2-2x-4?
Write it as x2 - 2x - 4 = 0, and solve with the quadratic formula (a = 1, b = -2, c = -4).
What is the factorization of this trinomial -2x3 plus 2x2 plus 12x?
-2x3 + 2x2 + 12x = -2x(x2 - x - 6) = -2x(x2 + 2x - 3x - 6) = -2x[ x(x + 2) - 3(x + 2) ] = -2x(x - 3)(x + 2)
