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How do you factor x to the fourth power plus x squared plus 1?
(x2 - x + 1)(x2 + x + 1)
How do you factor x2 plus 7x plus 6?
x2 + 7x + 6 = (x + 6) (x + 1)
Factor x2-2x plus 1?
(x + 1)(x + 1)
Factor x3 plus 1?
(x + 1)(x2 - x + 1)
How do you factor x2 plus x-2?
(x + 2)(x - 1)
How do you factor x3-2x plus 1?
(x - 1)(x2 + x - 1)
What is the factor of x3 plus x2 plus 4x plus 4?
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
How do you factor x3 plus x2 plus x equals?
x3+x2+x First, factor out the x: x(x2+x+1) Could stop there, but the rest is factor-able using imaginary numbers: x(x+.5(1+i(3).5)(x+.5(1-i(3).5), where i = (-1).5, or sqrt(-1)
Factor completely x2 plus 6x plus 5?
x2 + 6x + 5 can be factored into (x+1) (x+5)
How do you Factor x cubed plus one divided by x plus one?
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
Factor X cubed plus x squared plus 2x plus 2?
Factor x3 + x2 + 2x + 2, by grouping. Group the first two terms and the last two terms. Then factor. First, factor x3 + x2 by pulling out an x2 term: x2(x + 1) Second, factor 2x + 2 by pulling out a 2: 2(x + 1) So, you now have: x2(x + 1) + 2(x + 1) If you have factored correctly, the terms inside the parentheses should be the same. Now regroup. ANS: (x + 1)(x2 + 2)
Factor the polynomial x2 plus 10x plus 9?
(x+1)(x+9)
