3 blocks east
The cyclist's displacement is the straight-line distance from their starting point to their final position. After traveling 1 mile north and then 1 mile east, the cyclist is located at the coordinates (1 mile east, 1 mile north). Moving 1 mile south returns them to the same latitude as their starting point, resulting in a final position of 1 mile east of the starting point. Therefore, the displacement is 1 mile east.
To find the total displacement, we consider the dog’s initial and final positions. The dog runs 80 meters to chase the ball and then returns 80 meters back to its starting point, resulting in no net displacement from that segment. Finally, when the dog runs 20 meters south, the total displacement is 20 meters to the south. Thus, the total displacement is 20 meters south.
The cyclist ends up 1 mile east of the starting point (unless the cycling takes place near the north or south pole!). So the displacement is 1 mile in an easterly direction.
Stopping distance is comprised of three main components: perception distance, reaction distance, and braking distance. Perception distance is the distance a vehicle travels while the driver recognizes a need to stop. Reaction distance is the distance covered during the driver's reaction time before applying the brakes. Finally, braking distance is the distance the vehicle travels from the moment the brakes are applied until it comes to a complete stop.
To find the displacement from the origin, we first note the movements: 30 m north (0, 30), 20 m east (20, 0), and 30√2 m southwest. The southwest direction implies a movement of 30√2 m at a 45-degree angle, which can be broken down into components: -30 m in the north-south direction and -30 m in the east-west direction. Adding these vectors, the final position is (20 - 30, 30 - 30) = (-10, 0). The displacement is the straight-line distance from the origin to this point, calculated as ( \sqrt{(-10)^2 + 0^2} = 10 ) m. Thus, the total displacement from the origin is 10 m in the west direction.
To conduct a mean square displacement calculation, you first need to track the position of a particle over time. Then, calculate the squared distance the particle has moved from its starting point at each time interval. Finally, average these squared distances to find the mean square displacement, which represents the average distance the particle has traveled from its starting point over time.
6.3 meter
well i guess because there are multiple ways to make a distance...let say A to B. it can go round and round before it finally reach B. You can go either direction to reach B. but when it comes to displacement, it demand the shortest distance to reach B, which is only one way to do it, i think this qualify displacement to have a specific direction.
Yes it is possible. Any body that travels in any particular closed shape (circle, square, triangle etc.) and returns to the point in which it started would have travelled a certain distance but the sum of its displacement would be nil. Example: A body travels in a 1 mile north, then 1 mile west, then one mile south and finally 1 mile east (ie. a square). The body has travelled a distance of 4 miles. The bodys displacement is 0 miles due to it returning to the point in which it started. You can calculate displacement using vectors. For this example assuming east is positive x and north is positive y: north + west + south + east y -x -y +x = 0
I Finally Found Someone was created on 1996-11-05.
They were finally APPREHENDED.
To calculate displacement using the work-energy equation, first calculate the work done on the object using the force applied and the distance moved. Then, equate the work done to the change in kinetic energy of the object using the work-energy equation: Work = Change in kinetic energy = 0.5 * mass * (final velocity^2 - initial velocity^2). Finally, rearrange the equation to solve for displacement.
I Finally Found Someone - album - was created on 2001-04-17.
Displacement measures the 'net' distance that a moving object covers during some period of time. It's just the short, straight distance from the starting point to the end-point, regardless of the path the object followed or how much total distance it had to go to get there. Example: If you walk a mile straight along the shoulder of a straight road, the distance is 1 mile AND the displacement is also 1 mile. If you kept crossing the road, back and forth, to stay in the shade of the trees on each side, the displacement at the end of your walk would still be 1 mile, but the distance would be a lot more. If you jump into the shallow end of the pool, do 50 laps, and climb out again at the shallow end, the distance you swam is 50 laps, but the displacement is just about zero ... you ended almost exactly where you started. Drop a hard rubber ball from 6-ft off the floor. Maybe it bounces a hundred times, down-up-down-up-down, before it finally stops bouncing and just lays there. The displacement is 6 feet ... the short straight distance from the start-point to the end-point.
it means finally you can see someone for what they really are
--When they finally do.
1 mile East