0
What else can I help you with?
What is the displacement of a cyclist who traveled 1 mile north then 1 mile east and then finally 1 mile south?
The cyclist's displacement is the straight-line distance from their starting point to their final position. After traveling 1 mile north and then 1 mile east, the cyclist is located at the coordinates (1 mile east, 1 mile north). Moving 1 mile south returns them to the same latitude as their starting point, resulting in a final position of 1 mile east of the starting point. Therefore, the displacement is 1 mile east.
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
If the displacement is negative 2 north and represents a positive displacement What is the direction?
south
A -2 displacement towards the north represents a positive displacement towards the south?
Indeed it is.
Que4 A walker walks 4 km to the east from his house and then 3 km to the north Determine the displacement of the walker?
To determine the displacement of the walker, we can use the Pythagorean theorem. The walker travels 4 km east and 3 km north, forming a right triangle with these two legs. The displacement (d) is the hypotenuse, calculated as ( d = \sqrt{(4^2 + 3^2)} = \sqrt{16 + 9} = \sqrt{25} = 5 ) km. Therefore, the displacement of the walker is 5 km in a direction northeast.
What is the displacement of a cyclist who travels 1 mile north then1 mile east and finally 1 mile south what is it?
1 mile East
What is the displacement of a cyclist who traveled 1 mile north then 1 mile east and then finally 1 mile south?
The cyclist's displacement is the straight-line distance from their starting point to their final position. After traveling 1 mile north and then 1 mile east, the cyclist is located at the coordinates (1 mile east, 1 mile north). Moving 1 mile south returns them to the same latitude as their starting point, resulting in a final position of 1 mile east of the starting point. Therefore, the displacement is 1 mile east.
What is the total displacement of a person that travels 80 meters due South than travels another 50 meters due north?
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
A car pulls out from its garage begins to head north for 10 km then heads east for 5km then heads south for 15km and finally comes to rest after heading north 5 km What is the displacement?
The displacement of the car is 5 km to the east.
An RV travels 45 km and stays the night at a KOA The next day it travels for 3 hours to the north traveling 110 km What is the displacement over the two days for the RV?
45/110=4090
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
What is the correct displacement for the following vectors 4 km south km north 5 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
If the displacement is negative 2 north and represents a positive displacement What is the direction?
south
Emily travels 30 km east to visit Victoria after wards she travels 40 km north to visit star she then returns to her point or origin what was her total displacement?
Displacement (Δx) is the change in position of an object.Δx = xf - xiwhere xf is the final position and xi is the initial position or point of origin.In this case, Emily travels away from xi, but ultimately ends up back where she started, so xi = xf.Since xi = xf,xf - xi = 0.Even though she traveled a distance of 70km, the total displacement is 0.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south .5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the displacement of a hiker who travels 3.0 km east and then 4.0 km north?
The displacement of the hiker can be found by treating the eastward and northward movements as vectors. Using the Pythagorean theorem, the displacement is the square root of the sum of the squares of the distances traveled in each direction. In this case, the displacement is √(3.0 km)^2 + (4.0 km)^2 = √(9 km^2 + 16 km^2) = √25 km^2 = 5.0 km. Therefore, the displacement of the hiker is 5.0 km in a direction that is 53.1 degrees north of east.
