The cyclist ends up 1 mile east of the starting point (unless the cycling takes place near the north or south pole!). So the displacement is 1 mile in an easterly direction.
The cyclist's displacement is the straight-line distance from their starting point to their final position. After traveling 1 mile north and then 1 mile east, the cyclist is located at the coordinates (1 mile east, 1 mile north). Moving 1 mile south returns them to the same latitude as their starting point, resulting in a final position of 1 mile east of the starting point. Therefore, the displacement is 1 mile east.
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
south
Indeed it is.
To determine the displacement of the walker, we can use the Pythagorean theorem. The walker travels 4 km east and 3 km north, forming a right triangle with these two legs. The displacement (d) is the hypotenuse, calculated as ( d = \sqrt{(4^2 + 3^2)} = \sqrt{16 + 9} = \sqrt{25} = 5 ) km. Therefore, the displacement of the walker is 5 km in a direction northeast.
1 mile East
The cyclist's displacement is the straight-line distance from their starting point to their final position. After traveling 1 mile north and then 1 mile east, the cyclist is located at the coordinates (1 mile east, 1 mile north). Moving 1 mile south returns them to the same latitude as their starting point, resulting in a final position of 1 mile east of the starting point. Therefore, the displacement is 1 mile east.
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
The displacement of the car is 5 km to the east.
45/110=4090
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
south
Displacement (Δx) is the change in position of an object.Δx = xf - xiwhere xf is the final position and xi is the initial position or point of origin.In this case, Emily travels away from xi, but ultimately ends up back where she started, so xi = xf.Since xi = xf,xf - xi = 0.Even though she traveled a distance of 70km, the total displacement is 0.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
The displacement of the hiker can be found by treating the eastward and northward movements as vectors. Using the Pythagorean theorem, the displacement is the square root of the sum of the squares of the distances traveled in each direction. In this case, the displacement is √(3.0 km)^2 + (4.0 km)^2 = √(9 km^2 + 16 km^2) = √25 km^2 = 5.0 km. Therefore, the displacement of the hiker is 5.0 km in a direction that is 53.1 degrees north of east.