The 4 inches is 4/12 of a foot or 1/3 foot. Length times width times height is the volume, so 2856 (the area in square feet) times 1/3 (the depth in feet) = 952 cubic feet.
184.08 square feet is needed.
How many squares with sides that are 6 inches long I needed to cover a square with a side length of 30 inches without overlapping
5 ft by 9 ft is 45 square feet. This requires 6,480 square inches to cover it.
195 12 inches x 12 inches is 1 square foot
54
144
184.08 square feet is needed.
How many squares with sides that are 6 inches long I needed to cover a square with a side length of 30 inches without overlapping
5 ft by 9 ft is 45 square feet. This requires 6,480 square inches to cover it.
One side of a square is 10 inches long. How many one square inch tiles are needed to cover its area?
195 12 inches x 12 inches is 1 square foot
52 square inches for each layer, minimum with no overlap anywhere.
54
Each tile will cover 100 square inches. 12,000 square feet is 1,728,000 square inches. You will need 17,280 tiles.
To determine how many 3 x 9 tiles are needed to cover 30 square feet, first calculate the area of one tile. A 3 x 9 tile has an area of 27 square inches (3 inches x 9 inches). There are 144 square inches in a square foot, so 30 square feet is 4,320 square inches (30 x 144). Dividing 4,320 square inches by the area of one tile (27 square inches) gives approximately 160 tiles needed to cover 30 square feet.
how many squares with sides that are 6 inches long are needed to cover a squae with a side length of 30 inches without overlapping
To find out how many 6-inch squares are needed to cover a 30-inch square, first calculate the area of the larger square: (30 \times 30 = 900) square inches. The area of one 6-inch square is (6 \times 6 = 36) square inches. To determine the number of 6-inch squares required, divide the area of the larger square by the area of a smaller square: (900 \div 36 = 25). Therefore, 25 squares of 6 inches each are needed to cover the 30-inch square without overlapping.