Since 68 is not a perfect square, its square root is irrational.
Sqrt[5*radical(68)] = -6.4211 and +6.4211.
2 times the square root of 17
8.2It is: 8.2 rounded to the tenths place
√(68)√(34•2)√(17•2•2)this is as factorable as it gets, notice however, that we have a pair of primes.so we take that pair and pull it out as a single number:2•√(17)√(68)=2•√(17)
square-root of 68 times square-root of 68 = 68 (square-root of any number) squared is that number
Since 68 is not a perfect square, its square root is irrational.
The square root of 4,624 is 68.
The square root of 68 is 8.246211251 rounded to 9 decimal places.
They are; 8 and 9 but the square root of 68 is about 8.246211251
The idea is to find a perfect square among its factors, such as two square, three square, etc. In this case, the square root of 68, root(68), equals root(4 x 17) = root(4) x root(17) = 2 root(17).
2 square root 17
Sqrt[5*radical(68)] = -6.4211 and +6.4211.
2 times the square root of 17
The square roots are irrational.
Rounding, it's 8.25
68