mx = 5y + 4
7x + 6y + 5 = 0
If they have the same slope, then we know that Δy/Δx in the first line is equal to Δy/Δx in the second one. Let's solve the second equation for y then:
y = (5 + 7x) / -6
∴y = (-7/6)x - 5/6
So we know it's slope is -7/6. Now let's rearrange our other line appropriately:
y = (m/5)x - 4/5
So the slope of our second line is m/5, which we know is the same as the slope of our other line, -7/6. We can say then that:
m/5 = -7/6
∴m = -35/6 = -55/6 ≈ -5.8333...
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
Yes beccause: (y1-y2)/(x1-x2) = gradient
y=mx+c m=gradient c= is the y intercept in ur case: y=5x so gradient = 5
It is the gradient (slope) of the line.
To find the gradient on a quadratic graph, you first need to determine the derivative of the quadratic function, which is typically in the form (y = ax^2 + bx + c). The derivative, (y' = 2ax + b), represents the gradient at any point (x) on the curve. By substituting a specific (x) value into the derivative, you can find the gradient at that particular point on the graph. This gradient indicates the slope of the tangent line to the curve at the chosen point.
You find the gradient of the curve using differentiation. The answer is 0.07111... (repeating).
Yes beccause: (y1-y2)/(x1-x2) = gradient
y=mx+c m=gradient c= is the y intercept in ur case: y=5x so gradient = 5
See the many answers currently available. It equals the change in y divided by the corresponding change in x, as you go along any segment of the line.
It's 2. your equation is y=mx+b, so the gradient, or slope, is the "m" in the equation.
An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3
When the equation is given in the standard form: y = mx + c, the gradient is m. So here, y = 7x + 2 means m, the gradient, is 7.
It is the gradient (slope) of the line.
find the gradient
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To find the gradient on a quadratic graph, you first need to determine the derivative of the quadratic function, which is typically in the form (y = ax^2 + bx + c). The derivative, (y' = 2ax + b), represents the gradient at any point (x) on the curve. By substituting a specific (x) value into the derivative, you can find the gradient at that particular point on the graph. This gradient indicates the slope of the tangent line to the curve at the chosen point.
Look at the coefficient of the x term: the gradient of y = 3x + 12 is 3.An equation in the form:y = mx + cis such that the gradient and y intercept can be read directly from it:m is the gradientc is the y intercept.thank you