You substitute the variable for its value. Or you substitute the variables for each of the values.
There is no single formula for "solving" polygons. The answer will depend on what information you have and what information you require. Then there may or may not be a formula to enable you to find the required information. As a simple example, if you know two sides of a triangle, there is no formula that will determine the third side other than a range of possible values.
It is called a formula.
To evaluate means to find the value. Substitute the values of the variables and calculate the value. [You may need to solve for the values of the variables first.]
The quadratic equation is y=ax^2 +bx +c. So, you substitute in the values of a, b, and c to the quadratic formula (x= -b +/- \|b^2-4ac all over 2a) in order to find the x value then, substitute in x to the quadratic equation and solve. You will have point (x,y) to graph
Hire purchase is calculated using the simple interest formula, and interest is only calculated on the amount owing. A = S ( 1 + i.n) Where: A = Total amount after interest S = Starting amount after deposit has been subtracted (no interest) i = Interest rate (divide the % by 100, and then again by 12, 4, or 6 depending on the number of times interest will be calculated) n = number of time periods that the purchase agreement states to pay over (24 months, etc) Substituting the given values into the formula will give you the total amount to be paid after interest has been accrued. To calculate the repayments, you divide the answer derived as A (total amount) by the number of repayments (n) you have to make. It is a really simple process, and it will only ever use the simple interest formula. Hope this was helpful ^^
They are, when appropriate.
You substitute the variable for its value. Or you substitute the variables for each of the values.
You take the formula for simple interest, and create a function based off of it. The formula to generate simple interest is: Interest = Principal * Rate * Time In this case "time" refers to the number of periods for which interest will be applied. In most cases you're going to want to solve this equation for interest. So, you write a JavaScript function that will do the math for you. The function should take Principal, Rate, and Time as parameters, and return Interest. function calculateSI ( p, r, t ){ //You want to check that p, r, and t are appropriate values and//types. I'll skip that here for brevityreturn p*r*t; } That's all there is to it. To call the function, you'd pass in values in the proper order, of define them in the call. Then you capture the returned value with a variable like so: var simpleInterest = calculateSI ( 5000, 0.12, 64 ); //simpleInterest would now hold the value of "38400." I've gone ahead and create a JSFiddle example for you in which I set up a form to deal with acquiring and displaying the values. That version also shows how to write a single function to solve for any of the missing variables. (See related link.)
You must substitute values for the variable.
=B4+B6 simple isn't it. I wonder if your question is different.
To calculate the simple interest earned on an investment, you can use the formula: Interest = Principal x Rate x Time. In this case, Alfred's principal amount is $4000, the interest rate is 6%, and the time period is 5 years. Plugging these values into the formula, we get: Interest = $4000 x 0.06 x 5 = $1200. Therefore, Alfred will receive $1200 in interest if he invests $4000 at a 6% simple interest rate for 5 years.
first wright the eqn then write their concentration at initial , used and then equilibrium. using the formula substitute the values given at equilibrium.
The values were self-interest.
Choose some values for x. Then calculate the corresponding values of y using the formula. Put these values in a table.Choose some values for x. Then calculate the corresponding values of y using the formula. Put these values in a table.Choose some values for x. Then calculate the corresponding values of y using the formula. Put these values in a table.Choose some values for x. Then calculate the corresponding values of y using the formula. Put these values in a table.
-- First, write the quadratic formula on the back of your hand:x = 1/2A [ -B ± sqrt(B2 - 4AC) ]-- Then, stare at your equation until it dawns on you thatA = 12B = -77C = -20-- Substitute these values of 'A', 'B', and 'C' into the quadratic formula,evaluate it for the two values of 'x', and the two solutions practicallyfall out on the floor and surrender, on their own.
RSeries = SummationI=1toN (RI) Simple answer; add them up.