Assuming you include the endpoints (9 and 19, in this case), the calculation you must do is:19 - 9 + 1
If you don't subtract the endpoints (the question would be phrased something like "... between 9 and 19"), you have to subtract one instead of adding one, at the end.
There are 10 one digit positive integers (0 - 9) and 9 one digit negative integers (-9 to -1) making 19 in all.
They are 10 and 15
9
The integers for 19 are simply the whole numbers that can be expressed as 19 plus or minus any integer. This means the integers include 19, 18, 20, 17, 21, and so on, extending infinitely in both directions. In mathematical terms, the set of integers for 19 can be represented as {19 + n | n ∈ ℤ}, where ℤ denotes the set of all integers.
The integers are -19, -18 and -17.
There are 10 one digit positive integers (0 - 9) and 9 one digit negative integers (-9 to -1) making 19 in all.
They are 10 and 15
Two consecutive integers whose sum is 19 is 10 & 9; 10+9 = 19.
The numbers are 9 and 10.
There are 9 integers.
7
The least common factor of any set of integers is 1.
7X - 19 = 44add 19 to each side7X = 63divide each sides integers by 7X = 9============check in original equation7(9) - 19 = 4463 - 19 = 4444 = 44======checks
9
11. They are 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, and 21.
9 of them.
The integers are -19, -18 and -17.