answersLogoWhite

0


Best Answer

Let the 3 consecutive numbers be (a-1), a, and (a+1)

So, (a-1) + (a) + (a+1) = 216

You add the left-hand side and get:

3a =216

You divide and get:

a = 216/3 = 72

So,

(a-1) = 72-1 = 71

a = 72

(a+1)= 72+1 = 73

Check: 71+72+73 = 216

User Avatar

Wiki User

14y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: Sum of 3 consecutive numbers is 216?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

What is the 3 consesecutive numbers of 216?

the sum of three consecutive numbers is 216. What are the three numbers?


Does the sum of any three consecutive counting numbers have a factor of 3?

Yes, the sum of any three consecutive counting numbers has a factor of 3.


3 consecutive even numbers that have a sum of 3?

Sorry. No sum of even numbers can be an odd number.


What is always the sum of three consecutive whole numbers?

The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.


What four consecutive 3-digit numbers is 866?

The numbers are 215, 216, 217 and 218.


What four consecutive 3 digit numbers is 866?

The numbers are 215, 216, 217, and 218.


What are the sum of 3 consecutive whole numbers is 72?

You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.


The sum of 3 consecutive numbers is 600 what is the least of these 3 numbers?

The least of the three numbers is 199.


The sum of 3 consecutive natural numbers is 123?

It can be, if the numbers are the right ones.


What are Sum of 3 consecutive numbers in 66?

The numbers are 21, 22 and 23.


The sum of 3 consecutive odd numbers is 59 what are the numbers?

The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.


What are three consecutive numbers that add up to 68?

There are no such whole numbers. The sum of three consecutive whole numbers must be a multiple of 3; as 68 is not a multiple of 3 (68 = 3 × 22 2/3) it cannot be the sum of three whole numbers.