Sum of 3 consecutive numbers is 216?

Answer 1

Let the 3 consecutive numbers be (a-1), a, and (a+1)

So, (a-1) + (a) + (a+1) = 216

You add the left-hand side and get:

3a =216

You divide and get:

a = 216/3 = 72

So,

(a-1) = 72-1 = 71

a = 72

(a+1)= 72+1 = 73

Check: 71+72+73 = 216