Let the 3 consecutive numbers be (a-1), a, and (a+1)
So, (a-1) + (a) + (a+1) = 216
You add the left-hand side and get:
3a =216
You divide and get:
a = 216/3 = 72
So,
(a-1) = 72-1 = 71
a = 72
(a+1)= 72+1 = 73
Check: 71+72+73 = 216
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∙ 14y agothe sum of three consecutive numbers is 216. What are the three numbers?
You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.
The least of the three numbers is 199.
The numbers are 21, 22 and 23.
The numbers are 3, 4 and 5.
the sum of three consecutive numbers is 216. What are the three numbers?
Yes, the sum of any three consecutive counting numbers has a factor of 3.
Sorry. No sum of even numbers can be an odd number.
The sum of 3 consecutive whole numbers is always equal to 3 times the middle number in that sequence.
The numbers are 215, 216, 217 and 218.
The numbers are 215, 216, 217, and 218.
You probably want to know "What are the 3 consecutive whole numbers whose sum is 72 ?" They are 23, 24, and 25.
The least of the three numbers is 199.
It can be, if the numbers are the right ones.
The numbers are 21, 22 and 23.
The sum of three consecutive odd numbers must be divisible by 3. As 59 is not wholly divisible by 3 the question is invalid. PROOF : Let the numbers be n - 2, n and n + 2. Then the sum is 3n which is divisible by 3. If the question refers to three consecutive numbers then a similar proof shows that the sum of these three numbers is also divisible by 3. Again, the question would be invalid.
There are no such whole numbers. The sum of three consecutive whole numbers must be a multiple of 3; as 68 is not a multiple of 3 (68 = 3 × 22 2/3) it cannot be the sum of three whole numbers.