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To find the positive number ( x ) that, when added to its reciprocal ( \frac{1}{x} ), gives the maximum sum, we can express the sum as ( S = x + \frac{1}{x} ). By using calculus, we can determine that this function reaches its minimum at ( x = 1 ), which means that the maximum sum occurs symmetrically around that point. Therefore, the maximum sum ( S ) occurs at ( x = 1 ), giving ( S = 1 + 1 = 2 ).

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2mo ago

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