Q: Sum of two consecutive odd integers is 244 what is the smallest integer?

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integers are a, a + 1 and a + 2. a + 5(a + 2) = -244 ie 6a = -234 so a = -39 and the other two are -40 and -41.

15% off of 244 = 207.40 = 15% discount applied to 244 = 244 - (15% * 244) = 244 - (0.15 * 244) = 244 - 36.6 = 207.4 or 244 * 85% = 244 * 0.85 = 207.4

244

122x2=244 61x4=244

244 as a percentage of 97.6 is 250% But 97.6 as a percentage of 244 is 40%

Related questions

The sum is four.

249

Let n be the first integer, then n+1, n+2 and n+3 are the other three integers We have 4n+6=244 or 4n=238 but 4 does not go into 238 evenly so we CAN'T find 4 integers that work!

Call the lowest of the even integers n. Then from the problem statement, n + n + 2 + n + 4 = n + 6 =244. Collecting like terms results in 4n + 12 = 244, or 4n = 244 - 12 = 232, or n = 232/4 or 58. The consecutive even integers are therefore, 58, 60, 62, and 64.

58, 60, 62, 64

integers are a, a + 1 and a + 2. a + 5(a + 2) = -244 ie 6a = -234 so a = -39 and the other two are -40 and -41.

244

The numbers are 244 and 245.

It is 14+720k where k is any integer.

The numbers are 244, 246 and 248.

244 + 246 + 248 = 738.

20hours 16minutes, IF they're on consecutive days.