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Let n be the first integer, then n+1, n+2 and n+3 are the other three integers We have 4n+6=244 or 4n=238 but 4 does not go into 238 evenly so we CAN'T find 4 integers that work!

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Q: What are four consecutive integers that have the sum of 244?
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Related questions

The sum of 2 consecutive odd integers is 244 What is the sum of the smaller integer?

The sum is four.


Find four consecutive even integers whose sum is 244?

58, 60, 62, 64


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Call the lowest of the even integers n. Then from the problem statement, n + n + 2 + n + 4 = n + 6 =244. Collecting like terms results in 4n + 12 = 244, or 4n = 244 - 12 = 232, or n = 232/4 or 58. The consecutive even integers are therefore, 58, 60, 62, and 64.


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