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Let n be the first integer, then n+1, n+2 and n+3 are the other three integers We have 4n+6=244 or 4n=238 but 4 does not go into 238 evenly so we CAN'T find 4 integers that work!

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Q: What are four consecutive integers that have the sum of 244?
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Related questions

The sum of 2 consecutive odd integers is 244 What is the sum of the smaller integer?

The sum is four.


Find four consecutive even integers whose sum is 244?

58, 60, 62, 64


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The sum of the first four non-negative, consecutive, even integers is 20.


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Call the lowest of the even integers n. Then from the problem statement, n + n + 2 + n + 4 = n + 6 =244. Collecting like terms results in 4n + 12 = 244, or 4n = 244 - 12 = 232, or n = 232/4 or 58. The consecutive even integers are therefore, 58, 60, 62, and 64.


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No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.


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