Let n be the first integer, then n+1, n+2 and n+3 are the other three integers We have 4n+6=244 or 4n=238 but 4 does not go into 238 evenly so we CAN'T find 4 integers that work!
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Call the lowest of the even integers n. Then from the problem statement, n + n + 2 + n + 4 = n + 6 =244. Collecting like terms results in 4n + 12 = 244, or 4n = 244 - 12 = 232, or n = 232/4 or 58. The consecutive even integers are therefore, 58, 60, 62, and 64.
21, 22, 23
The numbers are 51, 53, 55 and 57.
The sum of two consecutive integers will always be an odd number.
-2, -1, 0, 1