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Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches?
Wiki User
∙ 14y ago
One presumes that you want the length of the sides.
Our rectangle has sides x and x-5, The perimeter of a rectangle is just the sum of all four sides and in rectangles they come in pairs, so our equation is:
50=2x + 2(x-5) expand to:
50=2x +2x - 10 combine terms to:
50=4x - 10 add +10 to both sides:
10 + 50 = 4x - 10 +10 combine again
60 = 4x divide both sides by 4
60/4 = 4x/4 simplify
15 = x; therefore the sides are 15 and 10=15-5
Wiki User
∙ 14y ago
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