45 and 45/5 = 9
25 and 20 25 + 20 = 45 25 - 20 = 5
The sum of 45 and 246 is 291.
the only multiples of 5 are 30.35.40.45.50, and 55 the only sum to 9 is 45
It isthe number must end in 0 or 5, andthe sum of the digits (and the sum of the digits of that sum and so on), must be 9.
45 and 45/5 = 9
1, 3, 5, 9, 15, 45 (sum = 78).
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
5*9= 45
25 and 20 25 + 20 = 45 25 - 20 = 5
Answer: 45 4 + 5 = 9 x 5 = 45
45
20 and 25
The sum of 45 and 246 is 291.
The sum of two numbers is 45 and their difference is 5. What are the two numbers? Let's start by calling the two numbers we are looking for x and y. The sum of x and y is 45. In other words, x plus y equals 45 and can be written as equation A: x + y = 45 The difference between x and y is 5. In other words, x minus y equals 5 and can be written as equation B: x - y = 5
This type of sum is continuous proportion 5 and 45 are a and c formula:b=√ac √5*45=√225=15. So the mean proportional is 15.
They are 9 and 5