45 and 45/5 = 9
25 and 20 25 + 20 = 45 25 - 20 = 5
The sum of 45 and 246 is 291.
the only multiples of 5 are 30.35.40.45.50, and 55 the only sum to 9 is 45
It isthe number must end in 0 or 5, andthe sum of the digits (and the sum of the digits of that sum and so on), must be 9.
45 and 45/5 = 9
1, 3, 5, 9, 15, 45 (sum = 78).
The number is 45. The sum of its digits i.e. 4+5=9 Five times the sum of its digits i.e. 5 times 9 which is 45
5*9= 45
25 and 20 25 + 20 = 45 25 - 20 = 5
Answer: 45 4 + 5 = 9 x 5 = 45
45
20 and 25
The sum of two numbers is 45 and their difference is 5. What are the two numbers? Let's start by calling the two numbers we are looking for x and y. The sum of x and y is 45. In other words, x plus y equals 45 and can be written as equation A: x + y = 45 The difference between x and y is 5. In other words, x minus y equals 5 and can be written as equation B: x - y = 5
The sum of 45 and 246 is 291.
This type of sum is continuous proportion 5 and 45 are a and c formula:b=√ac √5*45=√225=15. So the mean proportional is 15.
They are 9 and 5