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Think of the room as a box with four sides and a bottom. You want to know the area of the bottom. You know that the total area of all four sides added together is 120 square meters. You don't know the dimensions of each wall yet, but you know the ratio: length is twice the breadth or width. You know that the height of each side is 4 meters. So use those values to assign variables to the length and width of each side.

Each set of opposite sides will be equal in area. Say there are four sides: A, B, C and D. Sides A and C are opposite each other; sides B and D are opposite each other. Say sides A and C are the longer sides. That means that sides A and C are each 2x meters long and 4 meters high. The area of each side is 8x square meters. Sides B and D are the shorter sides. They are each x meters long and 4 meters high. The area of each side is 4x square meters. Now you have an expression for the area of each of the four sides. Set their sum equal to 120 square meters and solve for x.

8x + 8x + 4x + 4x = 120

24x = 120

x = 5

So x = 5. That tells you that the length of sides A and C is 2(5) = 10 meters each, and the length of sides B and D is 5 meters each. That gives you the information to solve for the area of the bottom of the box, or the floor. Just multiply the lengths: 5 x 10 = 50 square meters.

The floor of the room is 50 square meters. Two of the walls are 10 x 4 or 40 square meters each, and two of them are 5 x 4 or 20 square meters each. Altogether the four walls are 40 + 40 + 20 + 20 = 120 square meters.

Drawing a diagram in these kinds of problems really helps!

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Q: The area of four walls in a room is 120msquare the length is twice its breadth its height is 4mwhat is the area of the floor?
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