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A rectangle is a 2-dimensional object. It cannot have length and breadth AND height. If three dimensions are given, then two of them (eg breadth and height) must stand for the same thing.

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Q: How do you find height when length and breadth are given in rectangle?
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What is the area of the rectangle when the length and breadth are given?

All you need to do is length x breadth = area


How do you find the perimeter of a rectangle when given area?

You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.


How do you find the length of a rectangle given the width and area?

the area of a rectangle = length x widthwe can rearrange this to give uslength of a rectangle = area/ width


How do you find the height of a rectangle with the base and perimeter given?

Height = (Perimeter/2) - Base


What is the length and width of a rectangle if the area is 2200 square feet?

The length and width can't be determined since it is a rectangle. A length would need to be given, or it would have to be a square.