All you need to do is length x breadth = area
You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.You cannot. There are infinitely many possible answers.Given Area = A square units, select any value of L > sqrt(A) units and let B = A/L units.Then for every one of the infinitely many values of L, the rectangle with length L and breadth B, the area = L*B = L*(A/L) = A square units.The reason for selecting L > sqrt(A) is simply to ensure that each different value of L gives a different rectangle and you do not have the length and breadth of one rectangle being the breadth and length of another.
the area of a rectangle = length x widthwe can rearrange this to give uslength of a rectangle = area/ width
Height = (Perimeter/2) - Base
The length and width can't be determined since it is a rectangle. A length would need to be given, or it would have to be a square.
The breadth of a rectangle is the height.
Divide the area by the length of the rectangle
All you need to do is length x breadth = area
2(length+breadth)=Perimetre Length= (Perimetre/2)-Breadth Area=Length x breadth
56 cm Perimeter of a rectangle is given by 2(length + breadth). So, perimeter of given rectangle = 2(18 + 10) = 56
It has no length, breadth, height or position.
The answer depends on what information you are given: (volume, breadth and height), (surface are, breadth and height), (principle diagonal, breadth and height), (mass, density, breadth and height) or some other set.
Height = Area divided by Length
Let the length be x: 2*x = perimeter-(2*breadth) Then divide both sides by 2 to find the vallue of x
Measure the length and breadth of one face of the rectangle. Measure the thickness of the rectangle hollow piece. Multiply the length, breadth and thickness and this will give you the volume of the rectangular hollow piece in terms of cubic units. That is, if you measured the length, breadth and height in centimeters, the volume will be in cubic centimeters. Example: If the length of the piece is 10 cm, the breadth of the piece is 6 cm, and the thickness of the piece is 5 cm, the volume of the rectangular hollow piece is given by: 10 cm X 6 cm X 5 cm = 300 cubic cm or cm3
Length will equal the volume divided by the other two numbers.
you can't. you must be given the length, width and height as the formula is: lhw (length x height x width).