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Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
What is log(25) log(25)?
The expression "log(25) log(25)" represents the square of the logarithm of 25. If we let ( x = \log(25) ), then the expression simplifies to ( x^2 ). The value of ( \log(25) ) can be calculated as ( \log(5^2) = 2\log(5) ). Thus, ( \log(25) log(25) = (2\log(5))^2 = 4(\log(5))^2 ).
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
How do you solve log x plus 2 equals log 9?
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
How do you express the following as a formula which contains no logarithms. log E equals log m plus 2 log V?
To express the equation ( \log E = \log m + 2 \log V ) without logarithms, we can rewrite it using exponentiation. First, we can rewrite ( 2 \log V ) as ( \log V^2 ), leading to ( \log E = \log(m \cdot V^2) ). Exponentiating both sides gives us ( E = m \cdot V^2 ).
How old is mod ou 22lr cal 410 cal made by cobray serial number 000457 valued at?
abart 10
What is Characteristics Log value of 12468.3975?
4
Log x plus log 2 equals log 2?
log(x) + log(2) = log(2)Subtract log(2) from each side:log(x) = 0x = 100 = 1
Log 2 plus log 4 equals log 2x?
log(2) + log(4) = log(2x)log(2 times 4) = log(2x)2 times 4 = 2 times 'x'x = 4
What is log(25) log(25)?
The expression "log(25) log(25)" represents the square of the logarithm of 25. If we let ( x = \log(25) ), then the expression simplifies to ( x^2 ). The value of ( \log(25) ) can be calculated as ( \log(5^2) = 2\log(5) ). Thus, ( \log(25) log(25) = (2\log(5))^2 = 4(\log(5))^2 ).
If 3 log x - 2 log y?
1
How do you solve 3 to the power of negative 2x plus 2 equals 81?
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
Which expressions are equivalent to the one below log 2 - log 4?
-2
Given log 2 and log 3 how do you compute log 36?
log(36) = 1.5563To solve this problem without using a scientific calculator, factor 36 into 2*2*3*3, and use the formula:log(a*b) = log(a) + log(b)So, in this case:log(36) = log(2) + log(2) + log(3) + log(3) = 0.3010 + 0.3010 + 0.4772 + 0.4772 = 1.5564 (slight rounding error)
How do you solve log x plus 2 equals log 9?
log x + 2 = log 9 log x - log 9 = -2 log (x/9) = -2 x/9 = 10^(-2) x/9 = 1/10^2 x/9 = 1/100 x= 9/100 x=.09
How do you express the following as a formula which contains no logarithms. log E equals log m plus 2 log V?
To express the equation ( \log E = \log m + 2 \log V ) without logarithms, we can rewrite it using exponentiation. First, we can rewrite ( 2 \log V ) as ( \log V^2 ), leading to ( \log E = \log(m \cdot V^2) ). Exponentiating both sides gives us ( E = m \cdot V^2 ).
