No but the diagonals of a square, rhombus and a kite are perpendicular to each other
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
No but its diagonals are perpendicular to each other
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
No but its diagonals are perpendicular to each other.
If the diagonals are congruent and are perpendicular bisectors of each other then the parallelogram is a square. If the diagonals are not congruent but are perpendicular bisectors of each other then the figure would be a rhombus.
It has two diagonals, and they are perpendicular to each other.
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
No.
No but its diagonals are perpendicular to each other
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
It is a kite or a rhombus both of which have unequal diagonals that are perpendicular to each other creating right angles.
Yes, the diagonals of a rhombus are perpendicular to each other. Check out the related link at Mathopenref. It's pretty cool.
Yes they do.