A rhombus. (A square is, of course, also a rhombus.)
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
No but its diagonals are perpendicular to each other
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
No but the diagonals of a square, rhombus and a kite are perpendicular to each other
If the diagonals are congruent and are perpendicular bisectors of each other then the parallelogram is a square. If the diagonals are not congruent but are perpendicular bisectors of each other then the figure would be a rhombus.
No but its diagonals are perpendicular to each other.
It has two diagonals, and they are perpendicular to each other.
It is a rhombus whose diagonals are perpendicular and meeting each other at right angles.
No.
No but its diagonals are perpendicular to each other
If you are talking about the diagonals of a quadrilateral, the only quadrilateral that have diagonals that are perpendicular and bisect each other is a square, because a rectangle has bisecting diagonals, while a rhombus has perpendicular diagonals. And a square fits in both of these categories.
Not always but they are perpendicular in a square, a rhombus and a kite in that the diagonals intersect each other at 90 degrees
It is a kite or a rhombus both of which have unequal diagonals that are perpendicular to each other creating right angles.
Yes, the diagonals of a rhombus are perpendicular to each other. Check out the related link at Mathopenref. It's pretty cool.
Yes they do.