D = 60T where T is expressed in hours.
Speed describes the distance traveled by an object divided by the time in which the distance was traveled, if the direction is not specified.
d(t)=Vi(t)+((1/2)(a*t^2)) I just can't find anywhere to explain where that 1/2 constant comes from.
. The distance decreased.
because the speed is constant..
D = 60T where T is expressed in hours.
No. The total distance traveled divided by constant speed is the time interval.
Speed describes the distance traveled by an object divided by the time in which the distance was traveled, if the direction is not specified.
The distance traveled by an automobile moving at a constant velocity is equal to the product of the velocity and the time traveled. This relationship assumes no changes in velocity or direction during the motion.
Time affects the distance traveled by an object in motion through the formula distance = speed x time. The longer the time, the greater the distance traveled if the speed remains constant. Conversely, if the time is decreased, the distance traveled will also be less if the speed remains constant.
d(t)=Vi(t)+((1/2)(a*t^2)) I just can't find anywhere to explain where that 1/2 constant comes from.
The equation for constant speed is distance = speed x time, where distance is the total distance traveled, speed is the constant speed at which the object is moving, and time is the duration of travel.
In uniform linear motion, distance traveled increases linearly with time. This means that for every constant unit of time that passes, the object covers an equal amount of distance. The relationship between distance and time is constant and can be represented by a straight line on a distance-time graph.
. The distance decreased.
The distance traveled by a truck driving at a constant speed compared with time.
The distance traveled would depend on the spacecraft's speed and the escape velocity of the planet. The formula to calculate the distance traveled with constant acceleration is D = (1/2)at^2, where D is distance, a is acceleration, and t is time. By plugging in the values, you can find the distance traveled.
To find the distance traveled in the first 5 seconds, we multiply the average velocity by the time traveled. If the object's velocity is constant, this distance is equal to the velocity multiplied by the time.