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What is the formula for distance traveled as a function of time when an object is subject to constant acceleration?
Wiki User
∙ 13y ago
d(t)=Vi(t)+((1/2)(a*t^2))
I just can't find anywhere to explain where that 1/2 constant comes from.
Wiki User
∙ 13y ago
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What is the formula for distance traveled with constant acceleration?
If the car begins with zero speed, thenDistance = 1/2 (acceleration) x (time)2
Formula for distance traveled?
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
For a car traveling at a constant rate of 60 mph the distance traveled is a function of the time traveled. how do i express this relation as a function?
D = 60T where T is expressed in hours.
How do you calculate tota distance traveled when given velocity time and acceleration?
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
If you know the distance traveled and the time traveled can YOU determine an object and ACCELERATION?
no, you need to know its initial velocity to determine this; if initial velocity is zero then distance is 1/2 acceleration x time squared
When the body starts from rest and attain velocity v in time t with a constant acceleration the distance traveled by the body is?
The distance traveled by the body can be calculated using the equation s = (1/2)at^2, where s is the distance, a is the acceleration, and t is the time taken to reach velocity v from rest.
What is the formula for distance traveled with constant acceleration?
If the car begins with zero speed, thenDistance = 1/2 (acceleration) x (time)2
What is the equation relating acceleration the distance traveled and the time of fall.?
The equation relating acceleration, distance traveled, and time of fall is given by: distance = (1/2) * acceleration * time^2. This equation is derived from the kinematic equation for motion under constant acceleration.
Formula for distance traveled?
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
For a car traveling at a constant rate of 60 mph the distance traveled is a function of the time traveled. how do i express this relation as a function?
D = 60T where T is expressed in hours.
How do you calculate tota distance traveled when given velocity time and acceleration?
Assuming constant acceleration: distance = v(0) t + (1/2) a t squared Where v(0) is the initial velocity.
Is the total distance traveled divided by constant speed eual constant speed?
No. The total distance traveled divided by constant speed is the time interval.
Suppose you plot the distance traveled by an object at various times and you discover that the graph is not a straight line what does this indicate about the object acceleration?
If the graph of distance traveled vs. time is not a straight line, it indicates that the object's acceleration is not constant. Acceleration is the rate of change of velocity, so a non-linear distance-time graph suggests that the object's velocity is changing at a non-constant rate, causing a curved graph.
What is the distance an object travels each second for objects falling under constant acceleration?
For objects falling under constant acceleration (such as gravity), the distance an object travels each second is determined by the formula d = 0.5 * a * t^2, where "d" is the distance, "a" is the acceleration, and "t" is the time in seconds. This means that the distance traveled each second will increase quadratically as time passes.
What is mathematical formula for calculating acceleration?
Acceleration=Speed1-speed2/Distance traveled
How do you find the distance given only the initial velocity traveled time and final velocity?
You can use the equation: distance = (initial velocity + final velocity) / 2 * time. This formula assumes constant acceleration.
Did the acceleration of the marble increase as it traveled down the ramp?
Yes, the marble's acceleration increased as it traveled down the ramp because the force of gravity acting on it remained constant, but the distance covered by the marble increased. This results in a higher acceleration due to the increased speed gained as it moved farther down the ramp.
