distance
The distance between C and D + The distance between D and E + The distance between E and F. :o)
It depends on what information you have. You could use a ruler or tape measure. Or, if the information is given in the foorm of the coordinates of the end points you could find the length as follows: if the coordinates of the two end points are (a,b) and (c,d) then the length is sqrt[(a - c)2 + (b - d)2]
To plot the points A(-4, -3), B(4, -3), C(4, -7), and D(-4, -7), place them on a Cartesian plane according to their coordinates. Connect the points in the order A-B-C-D and back to A to form a rectangle. To find the length of AB, calculate the distance between points A and B using the formula: distance = |x₂ - x₁|, which yields |4 - (-4)| = 8 units. Thus, the length of AB is 8 units (B).
Let the two points be (a,b) and (c,d). Then the distance between D= sqrt [ (a-c)^2 + (b-d)^2] where ^2 means squared.
In the figure, a line through points C and D will represent the linear relationship between those two points in a coordinate system. This line can be described using the slope-intercept form if the coordinates of points C and D are known. Additionally, the line can be used to predict values or analyze trends related to the data represented by those points.
The distance between C and D + The distance between D and E + The distance between E and F. :o)
B.2 units
It depends on what information you have. You could use a ruler or tape measure. Or, if the information is given in the foorm of the coordinates of the end points you could find the length as follows: if the coordinates of the two end points are (a,b) and (c,d) then the length is sqrt[(a - c)2 + (b - d)2]
To plot the points A(-4, -3), B(4, -3), C(4, -7), and D(-4, -7), place them on a Cartesian plane according to their coordinates. Connect the points in the order A-B-C-D and back to A to form a rectangle. To find the length of AB, calculate the distance between points A and B using the formula: distance = |x₂ - x₁|, which yields |4 - (-4)| = 8 units. Thus, the length of AB is 8 units (B).
Depends on the metric defined on the space. The "normal" Euclidean metric for the distance between two points is the length of the shortest distance between them - ie the length of the straight line joining them. If the coordinates of the two points (in 2-dimensions) are (a,b) and (c,d) then the distance between them is sqrt([(a - c)2 + (b - d)2] This can be generalised to 3 (or more) dimensions. However, there are other metrics. One such is the "Manhattan metric" or the "Taxicab Geometry" which was developed by Minkowski. For more information on that, see http://en.wikipedia.org/wiki/Manhattan_metric
Let the two points be (a,b) and (c,d). Then the distance between D= sqrt [ (a-c)^2 + (b-d)^2] where ^2 means squared.
In the figure, a line through points C and D will represent the linear relationship between those two points in a coordinate system. This line can be described using the slope-intercept form if the coordinates of points C and D are known. Additionally, the line can be used to predict values or analyze trends related to the data represented by those points.
void PrintDist (double d) { printf ("the distance is %g", d); }
exactly one
5 its 4
To find the equation in standard form of the line that contains points C and D, you first need the coordinates of those points. The standard form of a line is expressed as Ax + By = C, where A, B, and C are integers, and A should be non-negative. Using the coordinates of points C and D, you can calculate the slope and use the point-slope form to convert it to standard form. If you provide the coordinates of points C and D, I can help you derive the equation.
16.7 is d ans