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How can you describe the graph of the equation ax by c?
The graph of ax + by = c is a straight line going through the points (0, c/b) and (c/a, 0).
Points A B and C lie along the same line What can these points be called?
Collinear.
What is the slope of line BC?
This depends on what the points are for B, and C.
Is points B and C are collinear?
If points B and C are collinear, it means that they lie on the same straight line. To determine if points B and C are collinear, you would need to know the coordinates or have a visual representation of the points.
Is c a symmetrical?
If you mean , is the letter 'C' symmetrical? Then the answer is YES!!! . It has one line of symmetry . The line of symmetry is an horizontal line through the letter 'C'.
How can you describe the graph of the equation ax by c?
The graph of ax + by = c is a straight line going through the points (0, c/b) and (c/a, 0).
The line y mx c passes through the points -2 -2 and 41?
This has infinite no. of solutions.
What do we call points A B and C are on the same line?
They are collinear points that lie on the same line
Points A B and C lie along the same line What can these points be called?
Collinear.
What is the slope of line BC?
This depends on what the points are for B, and C.
A line passes through the points 2 -2 and 1 5 find the equation of the line?
gradient = (-2-5) / (2-1) = -7 hence y = -7x + C Since a point on the line is (1,5) 5 = -7 + C from which we have C = 12 The equation is y = 12 - 7x
If points A B and C all lie in a straight line but the other points are not on the line how many different lines can be drawn if each line contains at least two points?
2 lines, I believe.
How many circles can pass through two given points?
It takes 3 non collinear points to define one specific circle. With only two points an infinite number of circles can be drawn. Proof: Given two points A, B draw the line between them. Then find the perpendicular bisector of the line AB. Any point on the perpendicular bisector is equidistant from the two original points, A and B. A circle with center C and radius AC will then pass through points A and B. There are infinite point C's on the perpendicular bisector so there are infinite circles. Given three points A, B and D you can find the perpendicular bisector for line segements AB and then the perpendicular bisector fof line segment BC. The two perpedicular bisectors will not be parallel because the points A, B and D are non collinear. This means the two perpeniducar bisectors will intercept at only one point C(like any two intercepting lines). This point C is equidistant from points A, B, and D. A circle with center C and radius AC will then pass through all three of the points. Since there is only one point C that lies on both perpendicular bisectors, there is only one circle possible.
Is points B and C are collinear?
If points B and C are collinear, it means that they lie on the same straight line. To determine if points B and C are collinear, you would need to know the coordinates or have a visual representation of the points.
How many circle can be drawn passing through two points?
There are infinite circles which can be drawn with 2 defined points.. Because if we have 2 points then we can draw infinite equal intersecting lines in infinite directions, These intersecting lines are the radii of the circles. Like : we have 2 points You can draw infinite isosceles triangles as taking the line joining the points For example (activity) : we have 2 points A, B so let's join A and B which will make line AB and so let's take another point C and place that point in such a way that AC = AB and we observe that there are infinite points which can be placed in such a way like how we marked C. Now draw a circle with center C and radius A, we will observe that the circle also cuts through B and so as we have infinite points like C, so we can have infinite circles ..... And so we conclude that infinite circles with different radii can be drawn through two defined distant points ...
What is the line through middle c called?
the legar line
What is the name of the postulate that states through any 3 points a circle can be formed?
There cannot be such a postulate because it is not true. Consider a line segment AB and let C be any point on the line between A and B. If the three points are A, B and C, there can be no circle that goes through them. It is so easy to show that the postulate is false that no mathematician would want his (they were mostly male) name associated with such nonsense. Well, if one of the points approach the line that goes through the other two points, the radius of the circle diverges. The line is the limit of the ever-growing circles. In the ordinary plane, the limit itself does not exist as a circle, but mathematicians have supplemented the plane with infinity to "hold" the centres of such "straight" circles.
