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What are the dimensions of a rectangle with perimeter of 78cm and an area of 108cm?
Since the perimeter equals the two lengths added to the two widths you can write this equation since you know the actual perimeter.
78cm = 2l + 2w
Since the area is the length multiplied by the width you can write this equation since you know the actual area.
108= lw
You have two variables (length and width) that you do not know. Sinceyou have two equations you can solve for the variables. you can use substitution or addition ifyou would like. I will use substitution.
l=108/w
78=2(108/w) + 2w
78=216/w + 2w
78w = 216 + 2w2
0 = 2w2 -78w + 216
w = 3cm or 36cm
now put both into the equations to find the length (l)
78 = 2l + 2(3 or 36)
78 = 2l + 6 or 72
2l = 72 or 6
l = 3cm or 36cm
Your dimensions are 36cm X 3cm
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The length of the rectangle is 7cm more than the widthThe perimeter is 78cm Find the rectangle?
The rectangle is 23cm x 16cmHalf the perimeter is 78 / 2= 39cm (which is one side and one end).39 - 7 = 32cm32 / 2 = 16cm (one end)16 + 7 = 23cm (one side)Proof:(23 + 16) x 2 = 78cm the perimeter.
The width of a retangle is fixed at 16cm what lenghts will make the perimeter greater than 78cm?
The perimeter of a rectangle is 2 x length + 2 x width. If the width is 16 then 78 = 2 x length + 2 x 16 2 x length = 78 - 32 = 46 length = 23. For the perimeter to be greater than 78 cm, the length must be greater than 23 cm
How tall is one meter and 78 cm?
1m 78cm = 5' 10.1"
How many cm are in 780mm?
1cm = 10mm so 780mm = 780/10 = 78cm
What is 48cm x 78 cm in ft?
48cm x 78cm is 3744 square cm or 4.03 square feet.
