The range of the function y=x^2 would be y is greater than or equal to 0 in this case. So pretty much just find the vertex of the function and what ever the y coordinate is set that as the lowest number for the range.
The "maximum" function.
a function whose range is in the real number
The smallest number is 1 and the largest number is 8. The range is the largest minus the smallest, so it is 8-1=7.
true
f(x) = 2 cos 3x The amplitude: A = |2| = 2 The maximum value of the function: 2 The minimum value of the function: -2 The range: [-2, 2]
The MIN Function determines the lowest number in a range
A number does not have a range and domain, a function does.
The range of the function y=x^2 would be y is greater than or equal to 0 in this case. So pretty much just find the vertex of the function and what ever the y coordinate is set that as the lowest number for the range.
The "maximum" function.
a function whose range is in the real number
The smallest number is 1 and the largest number is 8. The range is the largest minus the smallest, so it is 8-1=7.
the range is a positive real number
true
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
In Excel you can use the SMALL() function The small function can retrieve the smallest values from data based on rank. For example: =SMALL(range,1) // smallest =SMALL(range,2) // 2nd smallest =SMALL(range,3) // 3rd smallest
true