The range of the function y=x^2 would be y is greater than or equal to 0 in this case. So pretty much just find the vertex of the function and what ever the y coordinate is set that as the lowest number for the range.
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y=x^2
помогите плиз сократить дробь 3y^2-8y-6/4-9y^2
The range, usually of a function, is the set of value that the function can take. The integral range is a subset of the range consisting of integer values that the function can take.
4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
The domain is a subset of the values for which the function is defined. The range is the set of values that the function takes as the argument of the function takes all the values in the domain.