8, 9, 10, 11 & 12
Let x be firstLet x+2 be secondLet x+4 be third.x+x+2+x+4=573x+6=573x=51x=17x+2=19x+4=21
The perimeter measures 5,900 feet.
The perimeter of this parcel measures 1,870 feet.
you add up the measures of the sides Perimeter=a+b+c
The perimeter
Let x be firstLet x+2 be secondLet x+4 be third.x+x+2+x+4=573x+6=573x=51x=17x+2=19x+4=21
The perimeter measures 5,900 feet.
The perimeter of this parcel measures 1,870 feet.
you add up the measures of the sides Perimeter=a+b+c
The angle measures are 59, 60 and 61. Use algebra to figure this out. Let x = the first consecutive number, x + 1 the second and x + 2 the third. So you have x + x + 1 + x + 2 = 180 3x + 3 = 180 3x = 177 x = 59
20ft is the perimeter.
The perimeter of a rhombus is the sum of its 4 sides
The perimeter
Sum of five consecutive even numbers is 540. So the middle one is 540/5 = 108. The other four are 108-4, 108-2, 108+2 and 108+4. So the largest is 108+4 = 112 degrees.
Area is 584.24cm² Perimeter is 88cm
Perimeter = 4*4.5 = 18 feet
The perimeter of a triangle is the sum of its 3 sides.