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Which rectangle has the greater perimeter 6 centimeters by 4 centimeters 6.5 centimeters by 2 centimeters?

6x4 has a perimeter of 2*(6+4) = 2*10 = 20 cm 6.5x2 has a perimeter of 2*(6.5+2) = 2*8.5 = 17 cm So the first has the larger perimeter.


What is the maximum length of a rectangle if the perimeter is to be no greater than 60 centimeters and the width is 5 centimeters?

The maximum length is 25 cm.


The length of a rectangle is 7 centimeters greater than the width The perimeter is 54 centimeters Find the length and the width?

Length 17 cm. Width 10 cm.


What could be the perimeter of a rectangle with an area of 48 square centimeters?

Anything greater than 27.713cm (4 x √48).


If the length of a rectangle is 7 centimeters greater than the width. The perimeter is 54 centimeters. Find the length and the width.?

width:10,length;17 17*2+10*2=54


Can a rectangle have a greater perimeter and also have a greater area?

Of course, a rectangle can have a greater perimeter and a greater area. Simply double all the sides: the perimeter is doubled and the area is quadrupled - both bigger than they were.


Is 5.7 centimeters greater is or 5.3 centimeters?

5.7 is greater.


Which is greater 25 millimeters or 4 centimeters?

25 millimeters is only 2.5 centimeters; so the 4 centimeters is greater.


Length of a rectange is 5m greater than the width the perimeter is 84m2 what is the length and width?

Rectangular perimeter = 2(Length + Width) Width = a Length = a+5 Then, 84 = 2(a+a+5) 42 = 2a+5 (42-5)/2 = a = 18.5m = Width Length = a+5 = 23.5m


Will a rectangle with a greater perimeter also have a greater areea?

Yes.


the width of a rectangle is w centimeters. the length of this rectangle is three times its width. the perimeter of the rectangle is greater than 64 centimeters. give the inequality that represents all possible values of w?

Let's set up an inequality to represent all possible values of the width (w) of the rectangle given the information provided. The length of the rectangle is three times its width, so the length (L) can be expressed as L = 3w. The perimeter (P) of a rectangle is given by the formula: P = 2(L + w). The perimeter is greater than 64 centimeters, so we have P > 64. Now, substitute the expression for L from step 1 into the perimeter formula from step 2: P = 2(3w + w) Simplify the expression inside the parentheses: P = 2(4w) P = 8w Now, we have the perimeter in terms of the width: P = 8w. We already know that P > 64, so we can write the inequality: 8w > 64 To isolate w, divide both sides of the inequality by 8: w > 64 / 8 w > 8 So, the inequality representing all possible values of the width (w) is: w > 8 This means that the width of the rectangle must be greater than 8 centimeters for the perimeter to be greater than 64 centimeters.


Is 536 centimeters greater than 5.3 decameters?

Yes, 536 centimeters is greater than 5.3 decameters. Since 1 decameter equals 100 centimeters, 5.3 decameters is equal to 530 centimeters. Therefore, 536 centimeters is greater than 530 centimeters.